What is ${9} \dfrac{1}{4} - {8}\dfrac{1}{3}$?A. $\dfrac{11}{12}$ A. $\dfrac{11}{12}$ B. $ {1} \dfrac{11}{12}$ C. $ {2} \dfrac{11}{12}$ D. $ {4} \dfrac{11}{12}$ E. $ {3} \dfrac{11}{12}$
Show Answer Show The First Step 1. ${9} \dfrac{1}{4} - {8}\dfrac{1}{3}$$ = {9} + \dfrac{1}{4} - {8} - \dfrac{1}{3}$$ = {9} - {8}+ \dfrac{1}{4} - \dfrac{1}{3}$Show Next Step 2. $ = {1} + \dfrac{1}{4} - \dfrac{1}{3}$$ = \dfrac{4}{4} + \dfrac{1}{4} - \dfrac{1}{3}$Show Next Step 3. $ = \dfrac{{4}+{1}}{4} - \dfrac{1}{3}$$ = \dfrac{{5}}{4} - \dfrac{1}{3}$Show Next Step 4. $ =\dfrac{{5} \times {3}}{{4} \times {3}} - \dfrac{{1}\times {4}}{{3} \times {4}}$Show Next Step 5. $ = \dfrac{{15}}{{12}} - \dfrac{4}{12}$$ = \dfrac{{15}-{4}}{12}$$=\dfrac{11}{12}$ No More Steps Practice Again Correct! Nice work!
