Find the solution to the following system.
$ \left \{ \begin{array}{cc} {y}={4}{x}+{24}\\{3}{x}-{4}{y}={-31} \end{array} \right. $
A. ${x}={-5}, \;{y}={4}$
B. ${x}={4}, \;{y}={-5}$
C. ${x}={5}, \;{y}={4}$
D. ${x}={-5}, \;{y}={-4}$
E. ${x}={-4}, \;{y}={5}$
$ \left \{ \begin{array}{cc} {y}={4}{x}+{24}\\{3}{x}-{4}{y}={-31} \end{array} \right. $
A. ${x}={-5}, \;{y}={4}$
B. ${x}={4}, \;{y}={-5}$
C. ${x}={5}, \;{y}={4}$
D. ${x}={-5}, \;{y}={-4}$
E. ${x}={-4}, \;{y}={5}$
