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Find the solution to the following system.
$ \left \{ \begin{array}{cc} {y}={3}{x}+{10}\\{4}{x}-{7}{y}={-19} \end{array} \right. $

A. ${x}={-3}, \;{y}={1}$
B. ${x}={1}, \;{y}={-3}$
C. ${x}={3}, \;{y}={1}$
D. ${x}={-3}, \;{y}={-1}$
E. ${x}={-1}, \;{y}={3}$