Find the solution to the following system.
$ \left \{ \begin{array}{cc} {y}={4}{x}+{12}\\{2}{x}-{3}{y}={-16} \end{array} \right. $
A. ${x}={-2}, \;{y}={4}$
B. ${x}={4}, \;{y}={-2}$
C. ${x}={2}, \;{y}={4}$
D. ${x}={-2}, \;{y}={-4}$
E. ${x}={-4}, \;{y}={2}$
$ \left \{ \begin{array}{cc} {y}={4}{x}+{12}\\{2}{x}-{3}{y}={-16} \end{array} \right. $
A. ${x}={-2}, \;{y}={4}$
B. ${x}={4}, \;{y}={-2}$
C. ${x}={2}, \;{y}={4}$
D. ${x}={-2}, \;{y}={-4}$
E. ${x}={-4}, \;{y}={2}$
