Find the solution to the following system.

$ \left \{ \begin{array}{cc} {y}={3}{x}+{10}\\{4}{x}-{7}{y}={-19} \end{array} \right. $

A. ${x}={-3}, \;{y}={1}$

B. ${x}={1}, \;{y}={-3}$

C. ${x}={3}, \;{y}={1}$

D. ${x}={-3}, \;{y}={-1}$

E. ${x}={-1}, \;{y}={3}$

$ \left \{ \begin{array}{cc} {y}={3}{x}+{10}\\{4}{x}-{7}{y}={-19} \end{array} \right. $

A. ${x}={-3}, \;{y}={1}$

B. ${x}={1}, \;{y}={-3}$

C. ${x}={3}, \;{y}={1}$

D. ${x}={-3}, \;{y}={-1}$

E. ${x}={-1}, \;{y}={3}$