Find the solution to the following system.
$ \left \{ \begin{array}{cc} {y}={3}{x}+{14}\\{4}{x}-{3}{y}={-27} \end{array} \right. $
A. ${x}={-3}, \;{y}={5}$
B. ${x}={5}, \;{y}={-3}$
C. ${x}={3}, \;{y}={5}$
D. ${x}={-3}, \;{y}={-5}$
E. ${x}={-5}, \;{y}={3}$
$ \left \{ \begin{array}{cc} {y}={3}{x}+{14}\\{4}{x}-{3}{y}={-27} \end{array} \right. $
A. ${x}={-3}, \;{y}={5}$
B. ${x}={5}, \;{y}={-3}$
C. ${x}={3}, \;{y}={5}$
D. ${x}={-3}, \;{y}={-5}$
E. ${x}={-5}, \;{y}={3}$
