Which of the following is equivalent to $\cfrac{3{x^3} - 2x^2 + 5}{x-{4}}$ ?
A. $3x^2 + {10}x + {40} + \cfrac{165}{x-{4}}$
B. $3x^2 + {10}x + \cfrac{45}{x-{4}}$
C. $3x^2 - {14}x - {56} - \cfrac{229}{x-{4}}$
D. $3x^2 - {14}x - \cfrac{61}{x-{4}}$
E. $3x^2 - {14}x + {56} + \cfrac{61}{x-{4}}$
No Solution StepsA. $3x^2 + {10}x + {40} + \cfrac{165}{x-{4}}$
B. $3x^2 + {10}x + \cfrac{45}{x-{4}}$
C. $3x^2 - {14}x - {56} - \cfrac{229}{x-{4}}$
D. $3x^2 - {14}x - \cfrac{61}{x-{4}}$
E. $3x^2 - {14}x + {56} + \cfrac{61}{x-{4}}$
