Current

The current in the 4-ohm resistor is
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			C
1	2	3	/
4	5	6	-
7	8	9	+
.	0	=	*

A. 1 amp. A. 1 amp.
B. 5 amps.
C. 4 amps.
D. $\dfrac{1}{5}$ amp.
E. $\dfrac{1}{4}$ amp.

Correct! Nice work!