Which of the following is equivalent to $\cfrac{3{x^3} - 4x^2 + 3}{x-{3}}$ ?
A. $3x^2 + {5}x + {15} + \cfrac{48}{x-{3}}$
B. $3x^2 + {5}x + \cfrac{18}{x-{3}}$
C. $3x^2 - {13}x - {39} - \cfrac{120}{x-{3}}$
D. $3x^2 - {13}x - \cfrac{42}{x-{3}}$
E. $3x^2 - {13}x + {39} + \cfrac{42}{x-{3}}$
No Solution StepsA. $3x^2 + {5}x + {15} + \cfrac{48}{x-{3}}$
B. $3x^2 + {5}x + \cfrac{18}{x-{3}}$
C. $3x^2 - {13}x - {39} - \cfrac{120}{x-{3}}$
D. $3x^2 - {13}x - \cfrac{42}{x-{3}}$
E. $3x^2 - {13}x + {39} + \cfrac{42}{x-{3}}$