Which of the following is equivalent to $\cfrac{4{x^3} - 4x^2 + 2}{x-{5}}$ ?
A. $4x^2 + {16}x + {80} + \cfrac{402}{x-{5}}$
B. $4x^2 + {16}x + \cfrac{82}{x-{5}}$
C. $4x^2 - {24}x - {120} - \cfrac{602}{x-{5}}$
D. $4x^2 - {24}x - \cfrac{122}{x-{5}}$
E. $4x^2 - {24}x + {120} + \cfrac{122}{x-{5}}$
No Solution StepsA. $4x^2 + {16}x + {80} + \cfrac{402}{x-{5}}$
B. $4x^2 + {16}x + \cfrac{82}{x-{5}}$
C. $4x^2 - {24}x - {120} - \cfrac{602}{x-{5}}$
D. $4x^2 - {24}x - \cfrac{122}{x-{5}}$
E. $4x^2 - {24}x + {120} + \cfrac{122}{x-{5}}$
